6/7n^2-4/35n

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Solution for 6/7n^2-4/35n equation: 


n in (-oo:+oo)

(6/7)*n^2-((4/35)*n) = 0

(6/7)*n^2+(-4/35)*n = 0

6/7*n^2-4/35*n = 0

DELTA = (-4/35)^2-(0*6/7*4)

DELTA = 16/1225

DELTA > 0

n = ((16/1225)^(1/2)+4/35)/(6/7*2) or n = (4/35-(16/1225)^(1/2))/(6/7*2)

n = 2/15 or n = 0

n in { 0, 2/15 }

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